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Kernel: Fix the return type for syscalls

The Process::Handler type has KResultOr<FlatPtr> as its return type.
Using a different return type with an equally-sized template parameter
sort of works but breaks once that condition is no longer true, e.g.
for KResultOr<int> on x86_64.

Ideally the syscall handlers would also take FlatPtrs as their args
so we can get rid of the reinterpret_cast for the function pointer
but I didn't quite feel like cleaning that up as well.
This commit is contained in:
Gunnar Beutner 2021-06-28 20:59:35 +02:00 committed by Andreas Kling
parent b6435372cc
commit 2a78bf8596
71 changed files with 313 additions and 301 deletions

View file

@ -8,14 +8,14 @@
namespace Kernel {
KResultOr<int> Process::sys$yield()
KResultOr<FlatPtr> Process::sys$yield()
{
REQUIRE_PROMISE(stdio);
Thread::current()->yield_without_holding_big_lock();
return 0;
}
KResultOr<int> Process::sys$donate(pid_t tid)
KResultOr<FlatPtr> Process::sys$donate(pid_t tid)
{
REQUIRE_PROMISE(stdio);
if (tid < 0)
@ -29,7 +29,7 @@ KResultOr<int> Process::sys$donate(pid_t tid)
return 0;
}
KResultOr<int> Process::sys$sched_setparam(int pid, Userspace<const struct sched_param*> user_param)
KResultOr<FlatPtr> Process::sys$sched_setparam(int pid, Userspace<const struct sched_param*> user_param)
{
REQUIRE_PROMISE(proc);
struct sched_param desired_param;
@ -54,7 +54,7 @@ KResultOr<int> Process::sys$sched_setparam(int pid, Userspace<const struct sched
return 0;
}
KResultOr<int> Process::sys$sched_getparam(pid_t pid, Userspace<struct sched_param*> user_param)
KResultOr<FlatPtr> Process::sys$sched_getparam(pid_t pid, Userspace<struct sched_param*> user_param)
{
REQUIRE_PROMISE(proc);
int priority;