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Everywhere: Remove redundant inequality comparison operators

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C++20 can automatically synthesize `operator!=` from `operator==`, so
there is no point in writing such functions by hand if all they do is
call through to `operator==`.

This fixes a compile error with compilers that implement P2468 (Clang
16 currently). This paper restores the C++17 behavior that if both
`T::operator==(U)` and `T::operator!=(U)` exist, `U == T` won't be
rewritten in reverse to call `T::operator==(U)`. Removing `!=` operators
makes the rewriting possible again.
See https://reviews.llvm.org/D134529#3853062
This commit is contained in:
Daniel Bertalan 2022-10-21 15:53:20 +02:00 • committed by Andrew Kaster
parent 4e406b0730
commit 4296425bd8
40 changed files with 1 additions and 180 deletions
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6
Userland/Libraries/LibGfx/Point.h
View file

@ -132,12 +132,6 @@ public:
return x() == other.x() && y() == other.y();
}
template<class U>
[[nodiscard]] bool operator!=(Point<U> const& other) const
{
return !(*this == other);
}
[[nodiscard]] Point<T> operator+(Point<T> const& other) const { return { m_x + other.m_x, m_y + other.m_y }; }
Point<T>& operator+=(Point<T> const& other)