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Everywhere: Remove redundant inequality comparison operators

C++20 can automatically synthesize `operator!=` from `operator==`, so
there is no point in writing such functions by hand if all they do is
call through to `operator==`.

This fixes a compile error with compilers that implement P2468 (Clang
16 currently). This paper restores the C++17 behavior that if both
`T::operator==(U)` and `T::operator!=(U)` exist, `U == T` won't be
rewritten in reverse to call `T::operator==(U)`. Removing `!=` operators
makes the rewriting possible again.
See https://reviews.llvm.org/D134529#3853062
This commit is contained in:
Daniel Bertalan 2022-10-21 15:53:20 +02:00 committed by Andrew Kaster
parent 4e406b0730
commit 4296425bd8
40 changed files with 1 additions and 180 deletions

View file

@ -477,12 +477,6 @@ public:
return location() == other.location() && size() == other.size();
}
template<class U>
[[nodiscard]] bool operator!=(Rect<U> const& other) const
{
return !(*this == other);
}
[[nodiscard]] Rect<T> operator*(T factor) const { return { m_location * factor, m_size * factor }; }
Rect<T>& operator*=(T factor)