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Kernel: Don't dispatch signals in Processor::enter_current()

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Signal dispatch is already taken care of elsewhere, so there appears to
be no need for the hack in enter_current().

This also allows us to remove the Thread::m_in_block flag, simplifying
thread blocking logic somewhat.

Verified with the original repro for #4336 which this was meant to fix.
This commit is contained in:
Andreas Kling 2022-01-29 13:57:39 +01:00
parent 3845c90e08
commit 677da0288c
5 changed files with 5 additions and 23 deletions
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13
Kernel/Scheduler.cpp
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@ -307,7 +307,7 @@ bool Scheduler::context_switch(Thread* thread)
// NOTE: from_thread at this point reflects the thread we were
// switched from, and thread reflects Thread::current()
enter_current(*from_thread, false);
enter_current(*from_thread);
VERIFY(thread == Thread::current());
if (thread->process().is_user_process() && thread->previous_mode() != Thread::PreviousMode::KernelMode && thread->current_trap()) {
@ -321,7 +321,7 @@ bool Scheduler::context_switch(Thread* thread)
return true;
}
void Scheduler::enter_current(Thread& prev_thread, bool is_first)
void Scheduler::enter_current(Thread& prev_thread)
{
VERIFY(g_scheduler_lock.is_locked_by_current_processor());
@ -337,15 +337,6 @@ void Scheduler::enter_current(Thread& prev_thread, bool is_first)
// the finalizer. Note that as soon as we leave the scheduler lock
// the finalizer may free from_thread!
notify_finalizer();
} else if (!is_first) {
// Check if we have any signals we should deliver (even if we don't
// end up switching to another thread).
if (!current_thread->is_in_block() && current_thread->previous_mode() != Thread::PreviousMode::KernelMode && current_thread->current_trap()) {
SpinlockLocker lock(current_thread->get_lock());
if (current_thread->state() == Thread::Running && current_thread->pending_signals_for_state()) {
current_thread->dispatch_one_pending_signal();
}
}
}
}