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Everywhere: Switch from (void) to [[maybe_unused]] (#4473)
Problem: - `(void)` simply casts the expression to void. This is understood to indicate that it is ignored, but this is really a compiler trick to get the compiler to not generate a warning. Solution: - Use the `[[maybe_unused]]` attribute to indicate the value is unused. Note: - Functions taking a `(void)` argument list have also been changed to `()` because this is not needed and shows up in the same grep command.
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103 changed files with 219 additions and 362 deletions
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@ -61,9 +61,7 @@ TEST_CASE(load_form)
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widgets.for_each([&](const JsonValue& widget_value) {
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auto& widget_object = widget_value.as_object();
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auto widget_class = widget_object.get("class").as_string();
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widget_object.for_each_member([&](auto& property_name, const JsonValue& property_value) {
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(void)property_name;
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(void)property_value;
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widget_object.for_each_member([&]([[maybe_unused]] auto& property_name, [[maybe_unused]] const JsonValue& property_value) {
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//dbgprintf("Set property %s.%s to '%s'\n", widget_class.characters(), property_name.characters(), property_value.serialized().characters());
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});
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});
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