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Everywhere: Switch from (void) to [[maybe_unused]] (#4473)
Problem: - `(void)` simply casts the expression to void. This is understood to indicate that it is ignored, but this is really a compiler trick to get the compiler to not generate a warning. Solution: - Use the `[[maybe_unused]]` attribute to indicate the value is unused. Note: - Functions taking a `(void)` argument list have also been changed to `()` because this is not needed and shows up in the same grep command.
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103 changed files with 219 additions and 362 deletions
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@ -31,7 +31,7 @@
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#ifdef DEBUG
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[[noreturn]] void __assertion_failed(const char* msg, const char* file, unsigned line, const char* func);
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# define ASSERT(expr) (static_cast<bool>(expr) ? (void)0 : __assertion_failed(# expr, __FILE__, __LINE__, __PRETTY_FUNCTION__))
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# define ASSERT(expr) (static_cast<bool>(expr) ? void(0) : __assertion_failed(# expr, __FILE__, __LINE__, __PRETTY_FUNCTION__))
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# define ASSERT_NOT_REACHED() ASSERT(false)
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#else
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# define ASSERT(expr)
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