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Everywhere: Switch from (void) to [[maybe_unused]] (#4473)

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Problem:
- `(void)` simply casts the expression to void. This is understood to
  indicate that it is ignored, but this is really a compiler trick to
  get the compiler to not generate a warning.

Solution:
- Use the `[[maybe_unused]]` attribute to indicate the value is unused.

Note:
- Functions taking a `(void)` argument list have also been changed to
  `()` because this is not needed and shows up in the same grep
  command.
This commit is contained in:
Lenny Maiorani 2020-12-20 16:09:48 -07:00 • committed by GitHub
parent 4421d98e30
commit 765936ebae
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GPG key ID: 4AEE18F83AFDEB23
103 changed files with 219 additions and 362 deletions
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2
Kernel/Assertions.h
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@ -31,7 +31,7 @@
#ifdef DEBUG
[[noreturn]] void __assertion_failed(const char* msg, const char* file, unsigned line, const char* func);
# define ASSERT(expr) (static_cast<bool>(expr) ? (void)0 : __assertion_failed(# expr, __FILE__, __LINE__, __PRETTY_FUNCTION__))
# define ASSERT(expr) (static_cast<bool>(expr) ? void(0) : __assertion_failed(# expr, __FILE__, __LINE__, __PRETTY_FUNCTION__))
# define ASSERT_NOT_REACHED() ASSERT(false)
#else
# define ASSERT(expr)