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Everywhere: Switch from (void) to [[maybe_unused]] (#4473)
Problem: - `(void)` simply casts the expression to void. This is understood to indicate that it is ignored, but this is really a compiler trick to get the compiler to not generate a warning. Solution: - Use the `[[maybe_unused]]` attribute to indicate the value is unused. Note: - Functions taking a `(void)` argument list have also been changed to `()` because this is not needed and shows up in the same grep command.
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parent
4421d98e30
commit
765936ebae
103 changed files with 219 additions and 362 deletions
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@ -515,11 +515,8 @@ int mknod(const char* pathname, mode_t mode, dev_t dev)
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__RETURN_WITH_ERRNO(rc, rc, -1);
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}
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long fpathconf(int fd, int name)
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long fpathconf([[maybe_unused]] int fd, [[maybe_unused]] int name)
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{
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(void)fd;
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(void)name;
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switch (name) {
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case _PC_PATH_MAX:
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return PATH_MAX;
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@ -530,10 +527,8 @@ long fpathconf(int fd, int name)
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ASSERT_NOT_REACHED();
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}
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long pathconf(const char* path, int name)
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long pathconf([[maybe_unused]] const char* path, int name)
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{
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(void)path;
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switch (name) {
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case _PC_PATH_MAX:
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return PATH_MAX;
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@ -614,9 +609,8 @@ void sysbeep()
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syscall(SC_beep);
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}
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int fsync(int fd)
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int fsync([[maybe_unused]] int fd)
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{
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UNUSED_PARAM(fd);
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dbgprintf("FIXME: Implement fsync()\n");
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return 0;
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}
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