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LibJS: Fix parsing of if (typeof "foo" === "string")

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Move parsing of unary expressions into the primary expression parsing
step so that `typeof` takes precedence over `===` in the above example.
This commit is contained in:
Andreas Kling 2020-03-25 09:51:54 +01:00
parent 7a5ef0a87f
commit 9ee7142227
1 changed files with 3 additions and 3 deletions
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6
Libraries/LibJS/Parser.cpp
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@ -216,6 +216,9 @@ NonnullRefPtr<Statement> Parser::parse_statement()
NonnullRefPtr<Expression> Parser::parse_primary_expression() NonnullRefPtr<Expression> Parser::parse_primary_expression()
{ {
if (match_unary_prefixed_expression())
return parse_unary_prefixed_expression();
switch (m_current_token.type()) { switch (m_current_token.type()) {
case TokenType::ParenOpen: { case TokenType::ParenOpen: {
consume(TokenType::ParenOpen); consume(TokenType::ParenOpen);
@ -320,9 +323,6 @@ NonnullRefPtr<ArrayExpression> Parser::parse_array_expression()
NonnullRefPtr<Expression> Parser::parse_expression(int min_precedence, Associativity associativity) NonnullRefPtr<Expression> Parser::parse_expression(int min_precedence, Associativity associativity)
{ {
if (match_unary_prefixed_expression())
return parse_unary_prefixed_expression();
auto expression = parse_primary_expression(); auto expression = parse_primary_expression();
while (match_secondary_expression()) { while (match_secondary_expression()) {
int new_precedence = operator_precedence(m_current_token.type()); int new_precedence = operator_precedence(m_current_token.type());