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Browser: Better handle ports in user input to url conversion

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Previously it was hard to enter a url with a port in browser:

"example.com:8080" -> Protocol not implemented: example.com

This patch makes an attempt at parsing the input as an url with http
first an validates if the url has a port.

"example.com:8080" -> "http://example.com:8080"
This commit is contained in:
networkException 2022-02-06 16:29:49 +01:00 • committed by Andreas Kling
parent e7b8498a4a
commit b28e861776
1 changed files with 8 additions and 8 deletions
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16
Userland/Applications/Browser/Tab.cpp
View file

@ -38,20 +38,20 @@
namespace Browser {
URL url_from_user_input(const String& input)
URL url_from_user_input(String const& input)
{
String url_string = input;
if (input.starts_with("?") && !g_search_engine.is_empty())
url_string = g_search_engine.replace("{}", URL::percent_encode(input.substring_view(1)));
return URL(g_search_engine.replace("{}", URL::percent_encode(input.substring_view(1))));
URL url = URL(url_string);
URL url_with_http_schema = URL(String::formatted("http://{}", input));
if (url_with_http_schema.is_valid() && url_with_http_schema.port().has_value())
return url_with_http_schema;
URL url = URL(input);
if (url.is_valid())
return url;
StringBuilder builder;
builder.append("http://");
builder.append(url_string);
return URL(builder.build());
return url_with_http_schema;
}
void Tab::start_download(const URL& url)