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LibGUI: Put all classes in the GUI namespace and remove the leading G

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This took me a moment. Welcome to the new world of GUI::Widget! :^)
This commit is contained in:
Andreas Kling 2020-02-02 15:07:41 +01:00
parent 2d39da5405
commit c5bd9d4ed1
337 changed files with 5400 additions and 4816 deletions
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12
DevTools/HackStudio/Project.cpp
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@ -74,14 +74,14 @@ struct Project::ProjectTreeNode : public RefCounted<ProjectTreeNode> {
ProjectTreeNode* parent { nullptr };
};
class ProjectModel final : public GModel {
class ProjectModel final : public GUI::Model {
public:
explicit ProjectModel(Project& project)
: m_project(project)
{
}
virtual int row_count(const GModelIndex& index) const override
virtual int row_count(const GUI::ModelIndex& index) const override
{
if (!index.is_valid())
return 1;
@ -89,12 +89,12 @@ public:
return node->children.size();
}
virtual int column_count(const GModelIndex&) const override
virtual int column_count(const GUI::ModelIndex&) const override
{
return 1;
}
virtual GVariant data(const GModelIndex& index, Role role = Role::Display) const override
virtual GUI::Variant data(const GUI::ModelIndex& index, Role role = Role::Display) const override
{
auto* node = static_cast<Project::ProjectTreeNode*>(index.internal_data());
if (role == Role::Display) {
@ -123,7 +123,7 @@ public:
return {};
}
virtual GModelIndex index(int row, int column = 0, const GModelIndex& parent = GModelIndex()) const override
virtual GUI::ModelIndex index(int row, int column = 0, const GUI::ModelIndex& parent = GUI::ModelIndex()) const override
{
if (!parent.is_valid()) {
return create_index(row, column, &m_project.root_node());
@ -132,7 +132,7 @@ public:
return create_index(row, column, node.children.at(row).ptr());
}
GModelIndex parent_index(const GModelIndex& index) const override
GUI::ModelIndex parent_index(const GUI::ModelIndex& index) const override
{
if (!index.is_valid())
return {};