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LibRegex: Don't print error message in Regex constructor
It should be up to the caller to decide what to do when parsing of the pattern fails.
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1 changed files with 1 additions and 4 deletions
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@ -45,11 +45,8 @@ Regex<Parser>::Regex(StringView pattern, typename ParserTraits<Parser>::OptionsT
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Parser parser(lexer, regex_options);
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Parser parser(lexer, regex_options);
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parser_result = parser.parse();
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parser_result = parser.parse();
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if (parser_result.error == regex::Error::NoError) {
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if (parser_result.error == regex::Error::NoError)
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matcher = make<Matcher<Parser>>(*this, regex_options);
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matcher = make<Matcher<Parser>>(*this, regex_options);
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} else {
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fprintf(stderr, "%s\n", error_string().characters());
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}
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}
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}
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template<class Parser>
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template<class Parser>
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