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Everywhere: Redundant inline specifier on constexpr functions (#3807)

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Problem:
- `constexpr` functions are decorated with the `inline` specifier
  keyword. This is redundant because `constexpr` functions are
  implicitly `inline`.
- [dcl.constexpr], §7.1.5/2 in the C++11 standard): "constexpr
  functions and constexpr constructors are implicitly inline (7.1.2)".

Solution:
- Remove the redundant `inline` keyword.
This commit is contained in:
Lenny Maiorani 2020-10-20 10:08:13 -06:00 • committed by GitHub
parent a40abd6ce3
commit d1fe6a0b53
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GPG key ID: 4AEE18F83AFDEB23
13 changed files with 43 additions and 43 deletions
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4
AK/Checked.h
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@ -104,7 +104,7 @@ struct TypeBoundsChecker<Destination, Source, true, true, false> {
};
template<typename Destination, typename Source>
inline constexpr bool is_within_range(Source value)
constexpr bool is_within_range(Source value)
{
return TypeBoundsChecker<Destination, Source>::is_within_range(value);
}
@ -289,7 +289,7 @@ constexpr Checked<T> operator*(const Checked<T>& a, const Checked<T>& b)
}
template<typename T>
constexpr inline Checked<T> operator/(const Checked<T>& a, const Checked<T>& b)
constexpr Checked<T> operator/(const Checked<T>& a, const Checked<T>& b)
{
Checked<T> c { a };
c.div(b.value());