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LibCpp: Differentiate between Type and NamedType

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This adds a new ASTNode type called 'NamedType' which inherits from
the Type node.

Previously every Type node had a name field, but it was not logically
accurate. For example, pointer types do not have a name
(the pointed-to type may have one).
This commit is contained in:
Itamar 2021-06-26 15:34:23 +03:00 • committed by Ali Mohammad Pur
parent 10cad8a874
commit d7aa831a43
5 changed files with 55 additions and 29 deletions
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8
Userland/DevTools/HackStudio/LanguageServers/Cpp/CppComprehensionEngine.cpp
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@ -227,8 +227,8 @@ String CppComprehensionEngine::type_of_property(const DocumentData& document, co
auto& parent = (const MemberExpression&)(*identifier.parent());
auto properties = properties_of_type(document, type_of(document, *parent.m_object));
for (auto& prop : properties) {
if (prop.name == identifier.m_name)
return prop.type->m_name->full_name();
if (prop.name == identifier.m_name && prop.type->is_named_type())
return ((NamedType&)prop.type).m_name->full_name();
}
return {};
}
@ -240,8 +240,8 @@ String CppComprehensionEngine::type_of_variable(const Identifier& identifier) co
for (auto& decl : current->declarations()) {
if (decl.is_variable_or_parameter_declaration()) {
auto& var_or_param = (VariableOrParameterDeclaration&)decl;
if (var_or_param.m_name == identifier.m_name) {
return var_or_param.m_type->m_name->full_name();
if (var_or_param.m_name == identifier.m_name && var_or_param.m_type->is_named_type()) {
return ((NamedType&)(*var_or_param.m_type)).m_name->full_name();
}
}
}