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			45 lines
		
	
	
	
		
			1.7 KiB
		
	
	
	
		
			C++
		
	
	
	
	
	
			
		
		
	
	
			45 lines
		
	
	
	
		
			1.7 KiB
		
	
	
	
		
			C++
		
	
	
	
	
	
| /*
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|  * Copyright (c) 2020, Stephan Unverwerth <s.unverwerth@serenityos.org>
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|  * Copyright (c) 2021-2022, David Tuin <davidot@serenityos.org>
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|  *
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|  * SPDX-License-Identifier: BSD-2-Clause
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|  */
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| 
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| #include <AK/StringView.h>
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| #include <AK/Vector.h>
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| #include <LibJS/ParserError.h>
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| #include <LibJS/Token.h>
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| 
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| namespace JS {
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| 
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| ErrorOr<String> ParserError::to_string() const
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| {
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|     if (!position.has_value())
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|         return String::from_deprecated_string(message);
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|     return String::formatted("{} (line: {}, column: {})", message, position.value().line, position.value().column);
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| }
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| 
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| DeprecatedString ParserError::to_deprecated_string() const
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| {
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|     if (!position.has_value())
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|         return message;
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|     return DeprecatedString::formatted("{} (line: {}, column: {})", message, position.value().line, position.value().column);
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| }
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| 
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| DeprecatedString ParserError::source_location_hint(StringView source, char const spacer, char const indicator) const
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| {
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|     if (!position.has_value())
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|         return {};
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|     // We need to modify the source to match what the lexer considers one line - normalizing
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|     // line terminators to \n is easier than splitting using all different LT characters.
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|     DeprecatedString source_string = source.replace("\r\n"sv, "\n"sv, ReplaceMode::All).replace("\r"sv, "\n"sv, ReplaceMode::All).replace(LINE_SEPARATOR_STRING, "\n"sv, ReplaceMode::All).replace(PARAGRAPH_SEPARATOR_STRING, "\n"sv, ReplaceMode::All);
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|     StringBuilder builder;
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|     builder.append(source_string.split_view('\n', SplitBehavior::KeepEmpty)[position.value().line - 1]);
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|     builder.append('\n');
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|     for (size_t i = 0; i < position.value().column - 1; ++i)
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|         builder.append(spacer);
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|     builder.append(indicator);
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|     return builder.to_deprecated_string();
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| }
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| 
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| }
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